Q. In a hydrogen atom, an electron moves in a circular orbit of radius $5.2 \times 10^{- 11}m$ and produces a magnetic induction of $12.56\ T$ at its nucleus. The current produced by the motion of the electron will be (Given $\mu_{0} = 4\pi \times 10^{- 7}Wb/A - m$)

A) $6.53 \times 10^{- 3}\ ampere$
B) $13.25 \times 10^{- 10}\ ampere$
C) $9.6 \times 10^{6}\ ampere$
D) $1.04 \times 10^{- 3}\ ampere$
Explanation

(d) $B = \frac{\mu_{0}}{4\pi}.\frac{2\pi i}{r} \Rightarrow 12.56 = 10^{- 7} \times \frac{2\pi \times i}{5.2 \times 10^{- 11}}$
$\Rightarrow i = 1.04 \times 10^{- 3}A$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.