The radius of the path of an electron moving at a speed of $3 imes 10^{7}\ m/s$ perpendicular to a magnetic field 5$ imes 10^{- 4}\ T$ is nearly

Question

The radius of the path of an electron moving at a speed of $3 	imes 10^{7}\ m/s$ perpendicular to a magnetic field 5$	imes 10^{- 4}\ T$ is nearly

Dr. Abubacker · Accepted Answer

(d) When a charged particle moves inside a uniform magnetic field then the radius of the circular path is
$r = \frac{mv}{Bq} = \frac{9.1 	imes 10^{- 31} 	imes 3 	imes 10^{7}}{5 	imes 10^{- 4} 	imes 1.6 	imes 10^{- 19}} = 0.34\ m = 34\ cm$

Q. The radius of the path of an electron moving at a speed of $3 \times 10^{7}\ m/s$ perpendicular to a magnetic field 5$\times 10^{- 4}\ T$ is nearly

Explanation

Reviewed by Dr. Abubacker

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