(c) When two parallel conductors are carrying current $I$ and $2I$ in same direction, then magnetic field at the midpoint is
$B = \frac{\mu_{0}2l}{2\pi r} - \frac{\mu_{0}I}{2\pi r} = \frac{\mu_{0}I}{2\pi r}$
When current $2I$ is switched off then magnetic field due to conductor carrying current $I$ is $B = \frac{\mu_{0}I}{2\pi r}$