The magnetic potential due to a magnetic dipole at a point on its axis distant 40 cm from its center is found to be $2.4 imes 10^{- 5}\ JA^{1}m^{- 1}$.The magnetic moment of the dipole will be

Question

The magnetic potential due to a magnetic dipole at a point on its axis distant 40 cm from its center is found to be $2.4 	imes 10^{- 5}\ JA^{1}m^{- 1}$.The magnetic moment of the dipole will be

Dr. Abubacker · Accepted Answer

(c) Here, $r = 40\ cm = 0.4\ m$
$	heta = 0{^\circ}$ (an axial line)
$V = 2.4 	imes 10^{- 5}J/A -$m; $M = ?$
As $V = \frac{\mu_{0}}{4\pi}\frac{M\ cos	heta}{r^{2}}$
$2.4 	imes 10^{- 5} = 10^{- 7}\frac{M 	imes 1}{(0.4)^{2}}$
$M = 38.4$ $Am^{2}$

Q. The magnetic potential due to a magnetic dipole at a point on its axis distant 40 cm from its center is found to be $2.4 \times 10^{- 5}\ JA^{1}m^{- 1}$.The magnetic moment of the dipole will be

Explanation

Reviewed by Dr. Abubacker

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