Q. A voltmeter has resistance of 2000 $\Omega$ and it can measure upto 2V. If we want to increase its range by 8V, then required resistance in series will be
A) 4000 $\Omega$
B) 6000 $\Omega$
C) 7000 $\Omega$
D) 8000 $\Omega$
Explanation
(d) $i_{g} = \frac{2}{2000} = \frac{1}{1000}\ $A;
New range, $V = 8V + 2V = 10V$
$R = \frac{V}{i_{g}} - G = \frac{10}{(1/1000)} - 2000 = 8000\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.