(b) $E = \frac{1}{2}\ mv^{2}\ \ \ \ or\ \ \ \ \sqrt{2\ E/m};$
$r = \frac{mv}{Bq} = \frac{m}{Bq}\sqrt{2E/m}$
Or $r\ = \frac{\sqrt{2Em}}{Bq}\ \ \ \ \ \ or\ \ \ \ r \propto \ \sqrt{m};$
As , $m_{e} < m_{P};\ \ so,\ r_{e} < r_{P}$
Therefore, trajectory of proton is less curved