Q. A particle of mass $M$ and charge $Q$ moving with velocity $\overrightarrow{v}$ describes a circular path of radius $R$ when subjected to a uniform transverse magnetic field of induction $B$. The work done by the field when the particle completes one full circle is
A) $BQv2\pi R$
B) $\left( \frac{Mv^{2}}{R} \right)2\pi R$
C) Zero
D) $BQ2\pi R$
Explanation
(c) $W = F.d\cos{90{^\circ}} = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.