A particle of mass $0.6\ g$ and having charge of $25\ nC$ is moving horizontally with a uniform velocity $1.2 imes 10^{4}\ ms^{- 1}$ in a uniform magnetic field, then the value of the magnetic induction is $(g = 10\ ms^{- 2})$

Question

A particle of mass $0.6\ g$ and having charge of $25\ nC$ is moving horizontally with a uniform velocity $1.2 	imes 10^{4}\ ms^{- 1}$ in a uniform magnetic field, then the value of the magnetic induction is $(g = 10\ ms^{- 2})$

Dr. Abubacker · Accepted Answer

(c) Particle will move with uniform velocity when it’s acceleration is zero
$i.e.,\ \left| F_{m} ight| = mg \Rightarrow mg = qvB$
$\Rightarrow B = \frac{mg}{qv} = \frac{0.6 	imes 10^{- 3} 	imes 10}{25 	imes 10^{- 9} 	imes 1.2 	imes 10^{4}} = 20\ T$

Q. A particle of mass $0.6\ g$ and having charge of $25\ nC$ is moving horizontally with a uniform velocity $1.2 \times 10^{4}\ ms^{- 1}$ in a uniform magnetic field, then the value of the magnetic induction is $(g = 10\ ms^{- 2})$

Explanation

Reviewed by Dr. Abubacker

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