Q. A 100 turns coil shown in figure carries a current of $2\ amp$ in a magnetic field $B = 0.2\ Wb/m^{2}$. The torque acting on the coil is
A) 0.32 $Nm$ tending to rotated the side $AD$ out of the page
B) 0.32 $Nm$ tending to rotated the side $AD$ into the page
C) 0.0032 $Nm$ tending to rotated the side $AD$ out of the page
D) 0.0032 $Nm$ tending to rotated the side $AD$ into the page
Explanation
(a) $\tau = NBiA = 100 \times 0.2 \times 2 \times (0.08 \times 0.1) = 0.32N \times m$
Direction can be found by Fleming’s left hand rule
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.