Q. Two long parallel copper wires carry currents of $5A$ each in opposite directions. If the wires are separated by a distance of $0.5m$, then the force between the two wires is
A) $10^{- 5}N$, attractive
B) $10^{- 5}N$, repulsive
C) $2 \times 10^{- 5}N$, attractive
D) $2 \times 10^{- 5}N$, repulsive
Explanation
(b) $F = 10^{- 7}\frac{2i_{1}i_{2}}{a} = 10^{- 7} \times \frac{2 \times 5 \times 5}{0.5} = 10^{- 5}N$ [repulsive]
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.