(a) $B_{1} = \frac{\mu_{0}I}{2R}$ $B_{2} = \frac{\mu_{0}(2I)}{2R}$ $B_{net} = \sqrt{B_{1}^{2} + B_{2}^{2}}$ $= \frac{\mu_{0}(I)}{2R}\sqrt{1 + 4} = \frac{\sqrt{5}\mu_{0}I}{2R}$
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Ph.D. in Physics with 19+ years of teaching experience.