(b) Two coils carry currents in opposite directions, hence net magnetic field at centre will be difference of the two fields.
$ie,\ \ \ \ B_{net} = \frac{\mu_{0}}{4\pi}\ .\ 2\pi N\left\lbrack \frac{i_{1}}{r_{1}} - \frac{i_{2}}{r_{2}} \right\rbrack$
$= \frac{10\mu_{0}}{2}\left\lbrack \frac{0.2}{0.2} - \frac{0.3}{0.4} \right\rbrack$
$= \frac{5}{4}\mu_{0}$