Q. A current carrying small loop behaves like a small magnet. If $A$ be its area and $M$ its magnetic moment, the current in the loop will be
A) $M/A$
B) $A/M$
C) $MA$
D) $A^{2}M$
Explanation
(a) $M = iA \Rightarrow i = M/A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.