Q. The forces existing between two parallel current carrying conductors is $F$. If the current in each conductor is doubled, then the value of force will be
A) $2F$
B) 4$\ F$
C) 5$\ F$
D) $F$/2
Explanation
(b) As, $F = \frac{\mu_{0}}{4\pi}\ \frac{2i_{1}i_{2}}{r}\ \ ie,\ F \propto i_{1}i_{2}.$ Therefore force will becomes four time $ie,\ 4F.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.