(d) $\tau_{\max} = MB$ or $\tau_{\max} = ni\pi r^{2}B$. Let number of turns in length $l$ be $n$, so $l = n(2\pi r)$ or $\alpha = \frac{l}{2\pi n}$
$\Rightarrow \ \tau_{\max} = \frac{ni\pi Bl^{2}}{4\pi^{2}n^{2}} = \frac{l^{2}iB}{4\pi\ n_{\min}} \Rightarrow \tau_{\max} \propto \frac{1}{n_{\min}} \Rightarrow n_{\min} = 1$