Q. Magnetic field intensity at the centre of coil of 50 turns, radius $0.5\ m$ and carrying a current of $2\ A$ is
A) $0.5 \times 10^{- 5}T$
B) $1.25 \times 10^{- 4}T$
C) $3 \times 10^{- 5}T$
D) $4 \times 10^{- 5}T$
Explanation
(b) $B = \frac{\mu_{0}Ni}{2r} = \frac{4\pi \times 10^{- 7} \times 50 \times 2}{2 \times 0.5} = 1.25 \times 10^{- 4}T$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.