An electron is accelerated by a potential difference of $12000\ volts$. It then enters a uniform magnetic field of $10^{- 3}T$ applied perpendicular to the path of electron. Find the radius of path. Given mass of electron $= 9 imes 10^{- 31}kg$ and charge on electron $= 1.6 imes 10^{- 19}C$

Question

An electron is accelerated by a potential difference of $12000\ volts$. It then enters a uniform magnetic field of $10^{- 3}T$ applied perpendicular to the path of electron. Find the radius of path. Given mass of electron $= 9 	imes 10^{- 31}kg$ and charge on electron $= 1.6 	imes 10^{- 19}C$

Dr. Abubacker · Accepted Answer

(b) $r = \frac{\sqrt{2mK}}{qB} = \frac{1}{B}\sqrt{\frac{2mV}{q}}$
$= \frac{1}{10^{- 3}}\sqrt{\frac{2 	imes 9 	imes 10^{- 31} 	imes 12000}{1.6 	imes 10^{- 19}}} = 0.367\ m = 36.7\ cm$

Q. An electron is accelerated by a potential difference of $12000\ volts$. It then enters a uniform magnetic field of $10^{- 3}T$ applied perpendicular to the path of electron. Find the radius of path. Given mass of electron $= 9 \times 10^{- 31}kg$ and charge on electron $= 1.6 \times 10^{- 19}C$

Explanation

Reviewed by Dr. Abubacker

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