Q. A particle of charge $e$ and mass $m$ moves with a velocity $v$ in a magnetic field $B$ applied perpendicular to the motion of the particle. The radius $r$ of its path in the field is
A) $\frac{Bv}{em}$
B) $\frac{ev}{Bm}$
C) $\frac{Be}{mv}$
D) $\frac{mv}{Be}$
Explanation
(d) $r = \frac{mv}{Bq} = \frac{mv}{Be}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.