Q. An arbitrary shaped closed coil is made of a wire of length $L$ and a current $I$ ampere is flowing in it. If the plane of the coil is perpendicular to magnetic field $\overrightarrow{B}$, the force on the coil is
A) Zero
B) $IBL$
C) $2IBL$
D) $\frac{1}{2}IBL$
Explanation
(a) As shown in figure, since $\overrightarrow{L} = 0$
Hence according to $\overrightarrow{F} = i\left( \overrightarrow{L} \times \overrightarrow{B} \right) \Rightarrow \overrightarrow{F} = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.