Q. A current of 3A is flowing in a linear conductor having a length of 40 cm. The conductor is placed in a magnetic field of strength 500 G and makes an angle of $30{^\circ}$ with the direction of the field. It experiences a force of magnitude
A) $3 \times 10^{- 4}\ $N
B) $3 \times 10^{- 2}\ $N
C) $3 \times 10^{2}\ $N
D) $3 \times 10^{4}\ $N
Explanation
(b) $F = ilB\sin{\theta = 3 \times 0.40 \times \left( 500 \times 10^{- 4} \right) \times \sin{30{^\circ}}}$
$= 3\ \times 10^{- 2}\ $N
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.