(a) Force on wire $B\ due\ to\ A,$
$F_{BA} = \frac{\mu_{0} \times 1 \times 2}{2\pi r} = \frac{\mu_{0}}{\pi r}\ towards\ C$
Force on wire $B\ due\ to\ \ C$
$\ F_{BC} =$ $\frac{\mu_{0} \times 2 \times 3}{2\pi r} = \frac{{3\mu}_{0}}{\pi r}\ towards\ \ A$
Clearly $F_{BC} > F_{BA}$ therefore force on $B$ is directed towards $A$