Q. A current $I$ flow in an infinitely long wire cross-section in the form of a semi-circular ring of radius R. The magnitude of the magnetic induction along its axis is

A) $\frac{\mu_{0}\ I}{2\pi^{2}\ R}$
B) $\frac{\mu_{0}\ I}{2\pi\ R}$
C) $\frac{\mu_{0}\ I}{4\pi\ R}$
D) $\frac{\mu_{0}\ I}{\pi^{2}\ R}$
Explanation

(d) Consider the wire to be made up of large number of thin wires of infinite length. Consider such wire of thickness $dl$ subtending an angle $d\theta$ at centre.
Current through this wire,
$dl = \frac{d\theta}{\pi}\ I,$
$\therefore$ Magnetic field at centre due to this portion.
[image:4_image132.emf]
$dB = \frac{\mu_{0}}{4\pi}\ .\frac{2dI}{R}$
$\ \ \ = \frac{\mu_{0}I}{2\pi^{2}R}\ d\theta$
Net magnetic field at the centre.
$B = \ \ \int_{- \pi/2}^{\pi/2}{dB}\cos\theta = \frac{\mu_{0}I}{2\pi^{2}R}$
$\ \ \ \ \ \ \ \ \ \ \int_{- \pi/2}^{\pi/2}{\cos\theta}d\theta = \frac{\mu_{0}I}{\pi^{2}R}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.