Q. A solenoid consists of 100 turns of wire and has a length of 10.0 cm. The magnetic field inside the solenoid when it carries a current of 0.500 A will be
A) $6.28 \times 10^{- 4}\ T$
B) $6.28 \times 10^{- 5}\ T$
C) $3.14 \times 10^{- 4}\ T$
D) None of these
Explanation
(a) If the solenoid is of infinite length and the point taken is inside the solenoid, then
$B_{in} = \mu_{0}ni$
$\ \ \ \ \ \ \ = 4\pi \times 10^{- 7} \times \frac{100}{10 \times 10^{- 2}} \times 0.5$
$\ \ \ \ \ \ \ = 6.28 \times 10^{- 4}\ T$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.