(c) Magnetic field due to different parts are
$B_{1} = 0$
$B_{2} = \frac{\mu_{0}}{4\pi}.\frac{\pi i}{r}\bigodot$
$B_{3} = \frac{\mu_{0}}{4\pi}.\frac{i}{r}\bigodot$
$\therefore B_{net} = B_{2} + B_{3} = \frac{\mu_{0}i}{4r} + \frac{\mu_{0}i}{4\pi r}$