Q. A uniform conducting wire $ABC$ has a mass of $10g$. A current of $2A$ flows through it. The wire is kept in a uniform magnetic field $B = 2T$. The acceleration of the wire will be
A) Zero
B) $12\ \ ms^{- 2}$ along $y$-axis
C) $1.2 \times 10^{- 3}ms^{- 2}$ along $y$-axis
D) $0.6 \times 10^{- 3}ms^{- 2}$ along $y$-axis
Explanation
(b) The given curved wire can be treated as a straight wire as shown
Force acting on the wire $AC,\ F = Bil = 2 \times 2 \times 3 \times 10^{- 2}$
$= 12 \times 10^{- 2}N$ along $y$-axis
So acceleration of wire $= \frac{F}{m} = \frac{12 \times 10^{- 2}}{10 \times 10^{- 3}} = 12\ m/s^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.