Q. In hydrogen atom, the electron is making 6.6 $\times 10^{15}\ rev\ s^{- 1}$ around the nucleus of radius of 53 $\mathring{\mathrm{A}}$. The magnetic field produced at the centre of the orbit is nearly
A) 0.14 $Wbm^{- 2}$
B) 1.4 $Wbm^{- 2}$
C) 14 $Wbm^{- 2}$
D) 140 $Wbm^{- 2}$
Explanation
(a) $B = \frac{\mu_{0}}{4\pi}\frac{2\pi i}{r} = \ \frac{\mu_{0}}{4\pi}\frac{2\pi}{r}$ $\times (ev)$
$= \ \frac{4\pi \times 10^{- 7} \times 1.6\ \times 10^{- 19} \times 6.6 \times 10^{15}}{2 \times 53\ \times 10^{- 10}}$
$= 0.14\ Wb\ m^{- 2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.