Q. A conductor in the form of a right angle $ABC$ with $AB = 3\ cm$ amd $BC = 4\ cm$ carries a current of $10\ A$. There is a uniform magnetic field of $5\ T$ perpendicular to the plane of the conductor. The force on the conductor will be
A) 1.5 $N$
B) 2.0 $N$
C) 2.5 $N$
D) 3.5 $N$
Explanation
(c) According to the question figure can be drawn as shown below
Force on the conductor $ABC =$ Force on the conductor $AC$
$= 5 \times 10 \times \left( 5 \times 10^{- 2} \right) = 2.5N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.