(b) $\overrightarrow{F} = - e\left( \overrightarrow{v} \times \overrightarrow{B} \right) \Rightarrow \overrightarrow{F} = - e\left\lbrack v\widehat{i} \times B\widehat{j} \right\rbrack = evB\lbrack - \widehat{k}\rbrack$
$i.e.$ Force on electron is acting towards negative $z$-axis. Hence particle will move in a circle in $xz$-plane