Q. A small bar magnet of moment $M$ is placed in a uniform field $H$. If magnet makes an angle of $30{^\circ}$ with field, the torque acting on the magnet is
A) $MH$
B) $\frac{MH}{2}$
C) $\frac{MH}{3}$
D) $\frac{MH}{4}$
Explanation
(b) $\tau = MH\sin\theta = MH\sin{30{^\circ}} = \frac{MH}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.