(a) A bar magnet having N-S pole, strength m and length 2I be placed in a uniform magnetic field of strength B making an angle $\theta$ with the direction of the magnetic field. Force on N-pole of the magnet=mB (along the direction of magnetic field B.)
Force on S-pole of the magnet $= mB$ (along the direction of magnetic field B.)
Force on S-pole of the magnet $= mB$ (opposite to the direction of magnetic field B).
Therefore, net magnetic force on the dipole is zero.