Q. At a certain place, horizontal component is$\sqrt{3}$ times the vertical component. The angle of dip at this place is
A) Zero
B) $\pi/3$
C) $\pi/6$
D) None of these
Explanation
(c) tan$\delta = \frac{V}{H} = \frac{V}{\sqrt{3}V} = \frac{1}{\sqrt{3}}$
$\therefore\delta = 30{^\circ} = \pi$/ 6 rad
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.