Q. Due to a small magnet, intensity at a distance $x$ in the end on position is $9\ gauss$. What will be the intensity at a distance $\frac{x}{2}$ on broad side on position
A) $9\ gauss$
B) $4\ gauss$
C) $36\ gauss$
D) $4.5\ gauss$
Explanation
(c) In C.G.S. $B_{axial} = 9 = \frac{2M}{x^{3}}$ …(i)
$B_{equatorial} = \frac{M}{\left( \frac{x}{2} \right)^{3}} = \frac{8M}{x^{3}}\ \ \ \ \ \ \ \ldots(ii)$
From equation (i) and (ii), $B_{equatorial} = 36\ gauss$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.