Q. A paramagnetic substance of susceptibility $3 \times 10^{- 4}$ is placed in a magnetic field of$\ 4 \times 10^{- 4}\ {Am}^{- 1}$ . Then the intensity of magnetization in the units of ${Am}^{- 1}\ $is
A) $1.33 \times 10^{8}$
B) $0.75 \times 10^{- 8}$
C) $12 \times 10^{- 8}$
D) $14 \times 10^{- 8}$
Explanation
(c) Susceptibility $(X) = \frac{intensity\ of\ magnetisation\ (I)}{magnetic\ field(B)}$
Or $\ \ \ I = xB$
$\therefore\ \ \ \ \ I = 3 \times 10^{- 4} \times 4 \times 10^{- 4}$
Or $\ \ \ I = 12 \times 10^{- 8}\ Am^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.