Q. Two normal uniform magnetic fields contain a magnetic needle making an angle 60${^\circ}$ with $F$. Then the ratio of $\frac{F}{H}$ is
A) $1\ :2$
B) $2\ :1$
C) $\sqrt{3}\ :1$
D) $1\ :\sqrt{3}$
Explanation
(d) From figure, at equilibrium
$\tan{60{^\circ} = \frac{H}{F}}$
$\Rightarrow \sqrt{3} = \frac{H}{F} \Rightarrow \frac{F}{H} = \frac{1}{\sqrt{3}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.