Q. At a certain place the horizontal component of the earth’s magnetic field is $B_{0}$ and the angle of dip is 45${^\circ}$. The total intensity of the field at that place will be
A) $B_{0}$
B) $\sqrt{2}$ $B_{0}$
C) 2 $B_{0}$
D) $B_{0}^{2}$
Explanation
(b) For $H = R\ \cos\delta$
$\therefore R = \frac{H}{\cos\delta}$
$= \frac{B_{0}}{\cos 45{^\circ}} = \sqrt{2}B_{0}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.