(d) In series, same current flows through two tangent galvanometer.
$i = \frac{2r\ H}{\mu_{0}n_{1}}\tan\theta_{1} = \frac{2r\ H}{\mu_{0}n_{2}}\tan\theta_{2}$
$\therefore\frac{n_{1}}{n_{2}} = \frac{\tan\theta_{1}}{\tan\theta_{2}} = \frac{tan60{^\circ}}{tan45{^\circ}} = \sqrt{3}$