Q. At a place the angle of dip is $30{^\circ}.$ If the horizontal component of earth’s magnetic field is $B_{H},$ then the total field intensity is

A) $\frac{B_{H}}{2}$
B) $\frac{2B_{H}}{\sqrt{3}}$
C) $B_{H}\sqrt{2}$
D) $B_{H}\sqrt{3}$
Explanation

(b) Angle of dip is defined as the angle at a particular point on the earth’s surface between the direction of the earth’s magnetic field and
$B_{H} = B\cos\delta$
Where $B$ is total field intensity, $B_{H}$ the horizontal component of earth’s magnetifc field and $\theta$ the dip angle.
Given, $\delta = 30{^\circ}$
$\because\ \cos{30{^\circ} = \frac{\sqrt{3}}{2}}$
$\therefore B = \frac{B_{H}}{\cos{30{^\circ}}} = \frac{2B_{H}}{\sqrt{3}\ }$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.