Q. The horizontal component of flux density of earth’s magnetic field is $1.7 \times 10^{- 5}$T. The value of horizontal component of intensity of earth’s magnetic field will be?
A) $24.5Am^{- 1}$
B) 13.5$\ Am^{- 1}$
C) 1.53$\ Am^{- 1}$
D) 0.35$\ Am^{- 1}$
Explanation
(b) Here, $B = 1.7 \times 10^{- 5}T,\ H = ?$
$H = \frac{B}{\mu_{0}} = \frac{1.7 \times 10^{- 5}}{4\pi \times 10^{- 7}} = 13.53\ Am^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.