Q. The horizontal component of the earth’s magnetic field is $0.22\ gauss$ and total magnetic field is $0.4\ gauss.$ The angle of dip is
A) $\tan^{- 1}(1)$
B) $\tan^{- 1}(\infty)$
C) $\tan^{- 1}(1.518)$
D) $\tan^{- 1}{(\pi)}$
Explanation
(c) By using $B_{H} = B\cos\phi$
$\Rightarrow \cos\phi = \frac{B_{H}}{B} = \frac{0.22}{0.4}$
$\Rightarrow \tan\phi = \frac{\sqrt{(0.4)^{2} - (0.22)^{2}}}{0.22}$
$\Rightarrow \phi = \tan^{- 1}{(1.518)}$
[image:5_image50.png]
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.