(d) Magnetic potential at a distance $d$ from the bar magnet on it’s axial line is given by
$V = \frac{\mu_{0}}{4\pi}.\frac{M}{d^{2}} \Rightarrow V \propto M \Rightarrow \frac{V_{1}}{V_{2}} = \frac{M_{1}}{M_{2}}$
$\Rightarrow \frac{V}{V_{2}} = \frac{M}{M/4} \Rightarrow V_{2} = \frac{V}{4}$