Q.
When a piece of a ferromagnetic substance is put in a uniform magnetic field, the flux density inside it is four times the flux density away from the piece. The magnetic permeability of the material(in $N/A^{2}$) is
A) 1
B) 2
C) 3
D) 4
Explanation
(d) Permeability is given by
$\mu = \frac{B}{H}$
When B is magnetic flux density and H the auxiliary field strength.
Given, $B = 4H,$
$\therefore\ \mu = \frac{4H}{H} = 4NA^{- 2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.