Q. When $2\ amperes$ current is passed through a tangent galvanometer, it gives a deflection of $30{^\circ}$. For $60{^\circ}$ deflection, the current must be
A) 1 $amp$
B) $2\sqrt{3}\ amp$
C) $4\ amp$
D) $6\ amp$
Explanation
(d) $i \propto \tan\phi \Rightarrow \frac{i_{1}}{i_{2}} = \frac{{\tan\phi}_{1}}{\tan\phi_{2}}$
$\Rightarrow \frac{2}{i_{2}} = \frac{\tan 30}{\tan 60} \Rightarrow i_{2} = 6\ amp$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.