(b) Suppose magnetic field is zero at point $P$ which lies at a distance $x$ from 10 unit pole. Hence at $P$
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$\frac{\mu_{0}}{4\pi}.\frac{10}{x^{2}} = \frac{\mu_{0}}{4\pi}.\frac{40}{(30 - x)^{2}} \Rightarrow x = 10cm$
So from stronger pole distance is $20\ cm$