Q. At a certain place the horizontal component of the earth’s magnetic field is $B_{0}$ and the angle of dip is $45{^\circ}$ then total intensity of field at that place will be
A) $B_{0}^{2}$
B) $2B_{0}$
C) $\sqrt{2}B_{0}$
D) $B_{0}$
Explanation
(c) Using the formula for total intensity
$I = \frac{B_{H}}{\cos\theta} = \frac{B_{H}}{\cos{45{^\circ}}}$
$\ \ \ = \frac{B_{0}}{1\sqrt{2}} = \sqrt{2}B$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.