Q. The angle of dip at a certain place on earth is $60{^\circ}$ and the magnitude of earth’s horizontal component of magnetic field is 0.26 G. The magnetic field at the place on earth is
A) 0.13 G
B) 0.26 G
C) 0.52 G
D) 0.65 G
Explanation
(c) Horizontal component of earth’s magnetic field is the component of earth’s magnetic field along the horizontal direction.
$\ \ \ \ B_{H} = B\cos\delta$
$\ 0.26 = B\cos{60{^\circ}}$
$\Rightarrow \ B = \frac{0.26}{\cos{60{^\circ}}} = 0.52\ G$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.