Q. A dip needle which is free to move in a vertical plane perpendicular to magnetic meridian will remain
A) Horizontal
B) Vertical
C) Neither horizontal nor vertical
D) Inclined
Explanation
(b) tan$\delta^{'} = \frac{tan\delta}{cos\theta} = \frac{tan\delta}{cos90{^\circ}} = \frac{tan\delta}{0} = \infty.$
${\therefore\ \delta}^{'} = 90{^\circ}$
$\therefore$ Dip needle will stand vertical.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.