Q. A loop of area $0.5m^{2}$ is placed in a magnetic field of strength 2 T in direction making an angle of $30{^\circ}$ with the field. The magnetic flux linked with the loop will be
A) $\frac{1}{2}$ Wb
B) $\sqrt{\frac{3}{2}}\ $Wb
C) 2 Wb
D) $\frac{\sqrt{3\ }}{2}$Wb
Explanation
(d) Here $A = 0.5\ m^{2},\ B = 2\ T,\theta = 30{^\circ}$
$\phi = BA\ cos\theta = 2 \times 0.5\ cos30{^\circ} = \frac{\sqrt{3}}{2}\ $Wb
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.