Q. The number of turns and radius of cross-section of the coil of a tangent galvanometer are doubled. The reduction factor $K$ will be
A) $K$
B) $2K$
C) $4K$
D) $K/4$
Explanation
(a) $K = \frac{2RB_{H}}{\mu_{0}N}\ \lbrack R =$ Radius, $N =$ number of turns]
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.