Q. The unit for molar susceptibility is
A) $m^{3}$
B) $kg$-$m^{- 3}$
C) $kg^{- 1}m^{3}$
D) No units
Explanation
(a) Molar susceptibility
$= \frac{Volume\ susceptibility}{Density\ of\ material} \times \ $molarcular weight
$= \frac{I/H}{\rho} \times M = \frac{I/H}{M/V} \times M$
So it’s unit is $m^{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.