(a) From Coulomb’s law, $F = \frac{\mu_{0}}{4\pi}\frac{m_{1}m_{2}}{r^{2}};where,m_{1},m_{2}$ are pole strengths
$\therefore\mu_{0} = \frac{4\pi r^{2}\ F}{m_{1}m_{2}} = \frac{\lbrack L^{2}\left( MLT^{- 2} \right)\rbrack}{(AL)^{2}} = \lbrack MLT^{- 2}A^{- 2}\rbrack$