Q. The dimensions of magnetic permeability are

A) $\lbrack MLT^{- 2}A^{- 2}\rbrack$
B) $\lbrack ML^{2}T^{- 2}A^{- 2}\rbrack$
C) $\lbrack ML^{2}T^{- 2}A^{- 1}\rbrack$
D) $\lbrack M^{- 1}LT^{- 2}A^{- 2}\rbrack$
Explanation

(a) From Coulomb’s law, $F = \frac{\mu_{0}}{4\pi}\frac{m_{1}m_{2}}{r^{2}};where,m_{1},m_{2}$ are pole strengths
$\therefore\mu_{0} = \frac{4\pi r^{2}\ F}{m_{1}m_{2}} = \frac{\lbrack L^{2}\left( MLT^{- 2} \right)\rbrack}{(AL)^{2}} = \lbrack MLT^{- 2}A^{- 2}\rbrack$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.